Brownstown, Illinois

Brownstown is a city in Wabash County, Illinois. The population as of the 2000 US Census was 65,812.

Brownstown is heavily characterized by population disparity, with 64% of residents living in the northern half of the city. The northern half is considered dense and urban, while the southern half is considered typically suburban.

Demographics
As of the census of 2000, there were 65,812 people, 31,339 households, and 27,652 families residing in the city.

The racial makeup of the city was 89.28% White, 5.04% African American, 1.28% Native American, 3.27% Asian, 0.01% Pacific Islander, 0.46% from other races, and 0.66% from two or more races. Hispanic or Latino of any race were 2.79% of the population.

In 1990, the median income for a household in the city was $35,718, and the median income for a family was $39,247.

The median income for a household in the city was $34,952, and the median income for a family was $39,224. The per capita income for the city was $15,215. About 16.6% of families and 21.3% of the population were below the poverty line.

Household income in the northern half of the city was $29,491, while income in the southern half was $38,018.

Education
According to the 2000 US Census:
 * 16.2% did not finish High School
 * 83.8% of citizens were high school graduates
 * 6.1% attended less than one year of college
 * 5.4% attended college for more than one year but did not finish


 * 11.6% of citizens held a college degree
 * 4.2% associates
 * 5.1% bachelors
 * 1.2% masters
 * 1.1% doctorate